document.write( "Question 282695: The perimeter of a rectangle is 120 feet. The width of the rectangle is equal to one-half the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #205269 by mananth(16946)\"\" \"About 
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let the length of the rectangle be x\r
\n" ); document.write( "\n" ); document.write( "the width is 1/2 *x\r
\n" ); document.write( "\n" ); document.write( "the perimeter is 2*L + 2*w\r
\n" ); document.write( "\n" ); document.write( "120= 2*x+ 2* (1/2 *x)\r
\n" ); document.write( "\n" ); document.write( "120 = 2x+x\r
\n" ); document.write( "\n" ); document.write( "120 =3x\r
\n" ); document.write( "\n" ); document.write( "120/3= x\r
\n" ); document.write( "\n" ); document.write( "40 =x\r
\n" ); document.write( "\n" ); document.write( "the width will be 1/2 of 40 = 20 feet\r
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