document.write( "Question 282695: The perimeter of a rectangle is 120 feet. The width of the rectangle is equal to one-half the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #205269 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the length of the rectangle be x\r \n" ); document.write( "\n" ); document.write( "the width is 1/2 *x\r \n" ); document.write( "\n" ); document.write( "the perimeter is 2*L + 2*w\r \n" ); document.write( "\n" ); document.write( "120= 2*x+ 2* (1/2 *x)\r \n" ); document.write( "\n" ); document.write( "120 = 2x+x\r \n" ); document.write( "\n" ); document.write( "120 =3x\r \n" ); document.write( "\n" ); document.write( "120/3= x\r \n" ); document.write( "\n" ); document.write( "40 =x\r \n" ); document.write( "\n" ); document.write( "the width will be 1/2 of 40 = 20 feet\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |