document.write( "Question 282713: Four numbers have a sum of 9900. The second exceeds the first by one-seventh of the first. The third exceeds the sum of the first two by 300. The fourth exceeds the sum of the first three by 300. Find the four numbers.\r
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Algebra.Com's Answer #205252 by richwmiller(17219)\"\" \"About 
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a+b+c+d=9900
\n" ); document.write( "b-a/7=a
\n" ); document.write( "c-300=a+b
\n" ); document.write( "d-300=a+b+c
\n" ); document.write( "a = 1050, b = 1200, c = 2550, d = 5100
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