document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282707>Question 282707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a square is 12 more than its perimeter. Find the length of a side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205240 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "let side be x\r<BR>\n" );
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document.write( "Area of square =Side * Side  = x^2\r<BR>\n" );
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document.write( "Perimeter of square =  4*side= 4x\r<BR>\n" );
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document.write( "Area is 12 times the perimeter \r<BR>\n" );
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document.write( "x^2 = 12 *4*x\r<BR>\n" );
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document.write( "x^2/x= 48\r<BR>\n" );
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document.write( "x=48\r<BR>\n" );
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document.write( "the side is 48\r<BR>\n" );
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