document.write( "Question 282706: If i needed 2 points to be in Y intercept form, what would the answer be for (-5,2) and (4,1)?
\n" ); document.write( "y=mx+b should bt the form. Thanks.
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Algebra.Com's Answer #205239 by oberobic(2304)\"\" \"About 
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y = mx+b is slope-intercept form, where
\n" ); document.write( "m = slope
\n" ); document.write( "b = y-intercept (defined by x=0)
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\n" ); document.write( "Two points can be used to draw a line.
\n" ); document.write( "(-5,2) and (4,1)
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\n" ); document.write( "You also can determine the slope by computing the rise over the run.
\n" ); document.write( "rise = change in y = y2 - y1
\n" ); document.write( "run = change in x = x2 - x1
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\n" ); document.write( "We can define either point what we want, but we have to keep consistent.
\n" ); document.write( "(x1, y1) = (-5, 2)
\n" ); document.write( "(x2, y2) = (4, 1)
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\n" ); document.write( "rise = 1-2 = -1
\n" ); document.write( "run = 4 -(-5) = 4+5 = 9
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\n" ); document.write( "So,
\n" ); document.write( "m = -1/9
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\n" ); document.write( "That means y= -1/9x + b
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\n" ); document.write( "Now we have to compute 'b' to ensure it goes through the points given.
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\n" ); document.write( "We know that when x=4, y=1
\n" ); document.write( "Substituting, we find 'b'
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\n" ); document.write( "1 = -1/9*4 + b
\n" ); document.write( "1 + 4/9 = b
\n" ); document.write( "9/9 + 4/9 = b
\n" ); document.write( "13/9 = b
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\n" ); document.write( "So, we now have the equation: y = -1/9x + 13/9
\n" ); document.write( "Slope = -1/9
\n" ); document.write( "y-intercept = (0, 13/9)
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\n" ); document.write( "The x-intercept occurs where y=0, so we can solve by substitution again.
\n" ); document.write( "0 = -1/9x + 13/9
\n" ); document.write( "The obvious answer is x=13, so the point is (13,0).
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\n" ); document.write( "Graphing is a good way to check your work.
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