document.write( "Question 282606: x^-x-30=0 I need help on how to figure this problem \n" ); document.write( "
Algebra.Com's Answer #205195 by oberobic(2304) ![]() You can put this solution on YOUR website! Assuming you problem is to solve: \n" ); document.write( ". \n" ); document.write( "x^2 -x -30 = 0 \n" ); document.write( ". \n" ); document.write( "Factoring this is the best approach. \n" ); document.write( "We notice that we need a + and a - term to result in -30. \n" ); document.write( "And the two factors need to 1 apart. \n" ); document.write( "There are a number of ways we can multiply two numbers to result in 30. \n" ); document.write( "3*10 = 30, but they are 7 apart. \n" ); document.write( "5*6 = 30, and they are 1 apart. So that's it. \n" ); document.write( ". \n" ); document.write( "(x -6)(x +5) = 0 \n" ); document.write( ". \n" ); document.write( "checking this using FOIL (first, outer, inner, last): \n" ); document.write( ". \n" ); document.write( "x*x + x*5 + (-6)x + (-6)*5 = x^2 -x -30. \n" ); document.write( ". \n" ); document.write( "So, the solutions that make the equation true are: x=6 and x= -5. \n" ); document.write( ". \n" ); document.write( "We also can graph it. \n" ); document.write( " |