document.write( "Question 282559: a student has 2 small books, five medium sized books, and three large ones. If all the books are different, how many ways can they be arranged on a shelf so that all books of the same size are together. \n" ); document.write( "
Algebra.Com's Answer #205174 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! The 2 small books have 2*1=2 arrangements. \n" ); document.write( "The 5 medium books have 5*4*3*2*1=120 arrangements. \n" ); document.write( "The 3 latge books fave 3*2*1=6 arrangemenys. \n" ); document.write( "3*2*1=6 different ways to arrange these 3 groups of books. \n" ); document.write( "Thus the total=2*120*6*6=8,640 different arrangements. \n" ); document.write( " |