document.write( "Question 282552: Find the perimeter of the square in which a circle of area 81 pi is inscribed.\r
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Algebra.Com's Answer #205143 by user_dude2008(1862)\"\" \"About 
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A=81pi ----> 81pi=pi*r^2 ----> 81=r^2 ----> r=9\r
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\n" ); document.write( "\n" ); document.write( "side length of square = 2*r = 2*9 = 18\r
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\n" ); document.write( "\n" ); document.write( "Perimeter = 4*18 = 72\r
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\n" ); document.write( "\n" ); document.write( "Answer: 72
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