document.write( "Question 282502: Container A holds a solutions that is 12% acid and container B holds a solution that is 25% acid. How much of each solution should one use to form 7 liters that is 15% acid ? \n" ); document.write( "

Algebra.Com's Answer #205111 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of 12% solution needed
\n" ); document.write( "Then 7-x=amount of 25% solution needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure acid in the 12% solution (0.12x) plus the amount of pure acid in the 25% solution (0.25(7-x)) has to equal the amount of pure acid after they are mixed together (0.15*7). So, our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.12x+0.25(7-x)=0.15*7 get rid of parens
\n" ); document.write( "0.12x+1.75-0.25x=1.05 subtract 1.75 from each side
\n" ); document.write( "0.12x-0.25x+1.75-1.75=1.05-1.75 collect like terms
\n" ); document.write( "-0.13x=-0.70 divide each side by -0.13
\n" ); document.write( "x=5.39 liters----------------amount of 12% solution needed
\n" ); document.write( "7-x=7-5.39=1.61 liters amount of 25% solution needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "5.39*0.12+1.61*0.25=0.15*7
\n" ); document.write( "0.6468+0.4025=1.05
\n" ); document.write( "1.049~~~1.05\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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