document.write( "Question 282483: Help...
\n" ); document.write( "A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current.\r
\n" ); document.write( "\n" ); document.write( "Ugggg
\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #205093 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current
\n" ); document.write( "--------------------
\n" ); document.write( "Write down what you know:
\n" ); document.write( "b = speed of the boat
\n" ); document.write( "c = speed of the current
\n" ); document.write( "Downstream the speed is b+c
\n" ); document.write( "Upstream it's b-c
\n" ); document.write( "The distance is the same
\n" ); document.write( "---------------------------
\n" ); document.write( "d = rt
\n" ); document.write( "20 = 4*(b+c) = 5*(b-c)
\n" ); document.write( "-----------------------
\n" ); document.write( "4b + 4c = 20
\n" ); document.write( "5b - 5c = 20
\n" ); document.write( "------------
\n" ); document.write( "b + c = 5
\n" ); document.write( "b - c = 4
\n" ); document.write( "------------ Add
\n" ); document.write( "2b = 9
\n" ); document.write( "b = 4.5 mph
\n" ); document.write( "------------
\n" ); document.write( "c = 1/2 mph
\n" ); document.write( "
\n" ); document.write( "
\n" );