document.write( "Question 282483: Help...
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document.write( "A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current.\r
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Algebra.Com's Answer #205093 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A sailboat travels 20 miles downstream in 4 hours. It returns in 5 hours. Find the speed of the sailboat in still water and the rate of the current \n" ); document.write( "-------------------- \n" ); document.write( "Write down what you know: \n" ); document.write( "b = speed of the boat \n" ); document.write( "c = speed of the current \n" ); document.write( "Downstream the speed is b+c \n" ); document.write( "Upstream it's b-c \n" ); document.write( "The distance is the same \n" ); document.write( "--------------------------- \n" ); document.write( "d = rt \n" ); document.write( "20 = 4*(b+c) = 5*(b-c) \n" ); document.write( "----------------------- \n" ); document.write( "4b + 4c = 20 \n" ); document.write( "5b - 5c = 20 \n" ); document.write( "------------ \n" ); document.write( "b + c = 5 \n" ); document.write( "b - c = 4 \n" ); document.write( "------------ Add \n" ); document.write( "2b = 9 \n" ); document.write( "b = 4.5 mph \n" ); document.write( "------------ \n" ); document.write( "c = 1/2 mph \n" ); document.write( " \n" ); document.write( " |