document.write( "Question 282287: The length of a rectangle is 1ft less than 3 times the width. There is 310 ft squared.Find the dimension of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #205089 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
l=3w-1
\n" ); document.write( "A=lw
\n" ); document.write( "A=310
\n" ); document.write( "310=lw
\n" ); document.write( "310=(3w-1)w
\n" ); document.write( "310=3w^2-w
\n" ); document.write( "\"0=3w%5E2-w-310\"
\n" ); document.write( "w=10.33333 or 31/3 ft so l=3(31/3)-1=30ft
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"3w%5E2%2B-1w%2B-310+=+0\") has the following solutons:
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\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1%29%5E2-4%2A3%2A-310=3721\".
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\n" ); document.write( " Discriminant d=3721 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1%2B-sqrt%28+3721+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"w%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+3721+%29%29%2F2%5C3+=+10.3333333333333\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%28-1%29-sqrt%28+3721+%29%29%2F2%5C3+=+-10\"
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\n" ); document.write( " Quadratic expression \"3w%5E2%2B-1w%2B-310\" can be factored:
\n" ); document.write( " \"3w%5E2%2B-1w%2B-310+=+3%28w-10.3333333333333%29%2A%28w--10%29\"
\n" ); document.write( " Again, the answer is: 10.3333333333333, -10.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-1%2Ax%2B-310+%29\"

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