document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282433>Question 282433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the units of a two-digit numeral is 5 more than the tens digit the number is 3 times the sum of its digits.find the numeral </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205069 by </B><A HREF=/tutors/aboutme.mpl?userid=dturpin53><B>dturpin53(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dturpin53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let a be the 10's digit and let b be the units digit.<BR>\n" );
document.write( "From the stated problem the units digit is 5 more than the tne's digit or in equation form:<BR>\n" );
document.write( "b = a + 5<BR>\n" );
document.write( "The number is 3 times the sum of the digits or in equation form we have:<BR>\n" );
document.write( "10a + b= 3( a + b)= 3a + 3b<BR>\n" );
document.write( " substituting the b value from the first equation into the second we have:<BR>\n" );
document.write( "10a + a + 5 = 3a + 3(a +5)= 3a + 3a + 15<BR>\n" );
document.write( "11a + 5 = 6a + 15<BR>\n" );
document.write( "5a = 10<BR>\n" );
document.write( "a = 2<BR>\n" );
document.write( "b = a + 5 = 2 + 5 = 7<BR>\n" );
document.write( "  is this correct, the number is 27, and the sum of digits is 9 and 3*9 = 27\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );