document.write( "Question 282424: What is the value of x?\r
\n" ); document.write( "\n" ); document.write( "0.5 ln (110-x)+0.5 ln (100-x) = 4.26\r
\n" ); document.write( "\n" ); document.write( "0.8 ln (200-x) + 0.2 ln (100-x) = 4.56 \n" ); document.write( "
Algebra.Com's Answer #205060 by dabanfield(803)\"\" \"About 
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1.) 0.5 ln (110-x)+0.5 ln (100-x) = 4.26
\n" ); document.write( "2.) 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56\r
\n" ); document.write( "\n" ); document.write( "1.) .5 ln(110-x) + .5 ln(100-x) = 4.26
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\n" ); document.write( ".5*(ln(110-x)+ ln(100-x)) = 4.26
\n" ); document.write( "ln(110-x) + ln(100-x) = 4.26/.5\r
\n" ); document.write( "\n" ); document.write( "Using the law ln a + ln b = ln (a+b):\r
\n" ); document.write( "\n" ); document.write( "ln((110-x)*(100-x)) = 8.52
\n" ); document.write( "By definition of ln we have:\r
\n" ); document.write( "\n" ); document.write( "(110-x)*(100-x) = e^8.52\r
\n" ); document.write( "\n" ); document.write( "Solve the above for x using the quadratic formula.\r
\n" ); document.write( "\n" ); document.write( "2.) 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56\r
\n" ); document.write( "\n" ); document.write( "Are you sure the equation above is written correctly? \r
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