document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282421>Question 282421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 cars A and B seperated by 400 Km started moving at 8a.m. towards each other with Va=100Km/h and Va=50 Km/h. At what time will the distance between them become 100 Km? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205056 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 cars A and B seperated by 400 Km started moving at 8a.m. towards each other with Va=100Km/h and Va=50 Km/h. At what time will the distance between them become 100 Km?\r<BR>\n" );
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document.write( "Let t be the time needed for the two cars together to travel 400-100 = 300 km.\r<BR>\n" );
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document.write( "Then, using the formula distance = rate*time, we have:\r<BR>\n" );
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document.write( "300 = 100*t + 50*t\r<BR>\n" );
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document.write( "Solve the above for t and add to 8:00a. </SPAN>\n" );
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