document.write( "Question 282360: This is the problem and they want an algebra solution.
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document.write( "Three tired and hungry men went to sleep with a bag of apples. One man woke up, ate 1/3 of the apples, then went back to sleep. Later a second man woke up and ate 1/3 of the remaining apples, then went back to sleep.Finally,the third man woke and ate 1/3 of the remaining apples. When he was finished there were 8 apples left. How many apples were in the bag originally? \n" );
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Algebra.Com's Answer #205028 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! This problem appears every couple weeks. \n" ); document.write( "x-x/3-1/3(x-x/3)-1/3(x-x/3-1/3(x-x/3))=8 \n" ); document.write( "x=27\r \n" ); document.write( "\n" ); document.write( "first guy ate 1/3*27=9 leaving 18 \n" ); document.write( "next guy ate 18/3=6 leaving 12 \n" ); document.write( "3rd guy at 12/3=4 leaving 8\r \n" ); document.write( "\n" ); document.write( "A simpler way to calculate by working backwards \n" ); document.write( "2/3x=8 \n" ); document.write( "x=12 \n" ); document.write( "2/3x=12 \n" ); document.write( "x=18 \n" ); document.write( "2/3x=18 \n" ); document.write( "x=27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |