document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34210>Question 34210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not have a textbook because I am home schooling. If anyone can help I would be grateful>\r<BR>\n" );
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document.write( "Al goes 8mph; Ben goes 22mph in the opposite direction. How many hours has Ben traveled before they are 180 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20500 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING AND TRY\r<BR>\n" );
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document.write( "Travel_Word_Problems/29256: A freight train leaves Kansas and travels due west. A passenger train departs at exactly the same time on a parallel track and travels due east at a speed that is twice the speed of the freight train. After 7 hours the trains are 945 miles apart. How fast is each train traveling?						<BR>\n" );
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document.write( "Answer 16084 by venugopalramana(1088) About Me  on 2006-03-05 11:24:01 (Show Source):						<BR>\n" );
document.write( "A freight train leaves Kansas and travels due west. A passenger train departs at exactly the same time on a parallel track and travels due east at a speed that is twice the speed of the freight train. After 7 hours the trains are 945 miles apart. How fast is each train traveling?						<BR>\n" );
document.write( "TRAINS ARE TRAVELLING IN OPPOSITE DIRECTIONS..SO THEIR RELATVE SPEED =SUM OF THEIR INDIVIDUAL SPEEDS						<BR>\n" );
document.write( "SPEED OF ONE TRAIN IS X MPH....SAY..SECOND TRAIN SPEED =2X..MPH....SO						<BR>\n" );
document.write( "RELATIVE SPEED =X+2X=3X...MPH						<BR>\n" );
document.write( "TIME =7 HRS						<BR>\n" );
document.write( "INTIAL DISTANCE BETWEEN THEM =0						<BR>\n" );
document.write( "FINAL DISTANCE BETWEEN THEM =945 MILES						<BR>\n" );
document.write( "SO DISTANCE CHANGE =945-0=945 MILES..HENCE						<BR>\n" );
document.write( "945 =7*3X=21X						<BR>\n" );
document.write( "X=945/21=45 MPH						<BR>\n" );
document.write( "SO THE 2 TRAINS TRAVELLED AT 45 AND 90 MPH. </SPAN>\n" );
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