document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4529>Question 4529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor<BR>\n" );
document.write( "(x-y)^2 - (x-z)^2 <BR>\n" );
document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2050 by </B><A HREF=/tutors/aboutme.mpl?userid=Pumuky><B>Pumuky(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Pumuky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Debes desarrollar las potencias:\r<BR>\n" );
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document.write( "(x^2+y^2-2xy)-(x^2+z^2-2xz)\r<BR>\n" );
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document.write( "x^2+y^2-2xy-x^2-z^2+2xz\r<BR>\n" );
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document.write( "y^2-2xy-z^2+2xz\r<BR>\n" );
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document.write( "Factor Común 2x\r<BR>\n" );
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document.write( "y^2-z^2+2x(z-y)\r<BR>\n" );
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document.write( "Puedes expresarlo de forma aparentemente más compleja. Como (y+z)(y-z)=y^2-z^2 Then\r<BR>\n" );
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document.write( "[(y+z)(y-z)]-2x(y-z) ==> (y-z) [(y+z)-2x]<BR>\n" );
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