document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282300>Question 282300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 inches more than twice its width. its area is 65 inches sq. find the length and width of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204995 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width =x\r<BR>\n" );
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document.write( "length = 2x+3\r<BR>\n" );
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document.write( "x(2x+3)= 65\r<BR>\n" );
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document.write( "2x^2+3x=65\r<BR>\n" );
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document.write( "2x^2+3x-65=0\r<BR>\n" );
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document.write( "2x^2+13x-10x-65=0\r<BR>\n" );
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document.write( "2x(x-6.5)-10(x-6.5)=0\r<BR>\n" );
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document.write( "(2x-10)(x-6.5)=0\r<BR>\n" );
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document.write( "x= 5 & 6.5\r<BR>\n" );
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document.write( "The length and breadth 5 & 13  \r<BR>\n" );
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