document.write( "Question 282316: solve the square root of 6x+19=x-6
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Algebra.Com's Answer #204991 by subudear(62)\"\" \"About 
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sqrt(6x+19)=x-6\r
\n" ); document.write( "\n" ); document.write( "squaring both the sides\r
\n" ); document.write( "\n" ); document.write( "6x + 19 = (x - 6)^2
\n" ); document.write( "6x + 19 = x^2 - 12x + 36
\n" ); document.write( "x^2 - 18x + 17 = 0
\n" ); document.write( "x^2 - 17x - x +17 = 0
\n" ); document.write( "x(x - 17) - (x - 17) = 0\r
\n" ); document.write( "\n" ); document.write( "(x - 17)(x - 1)=0\r
\n" ); document.write( "\n" ); document.write( "therefore x = 17 and 1 are the solutions.
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