document.write( "Question 282328: Bill's upstream canoe trip took 1.5 hours longer than the return trip. If he averaged 2 mph on the upstream trip and 3 mph on the return trip, then how long was the upstream trip? \n" ); document.write( "
Algebra.Com's Answer #204989 by mananth(16946)\"\" \"About 
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Bill's upstream canoe trip took 1.5 hours longer than the return trip. If he averaged 2 mph on the upstream trip and 3 mph on the return trip, then how long was the upstream trip? \r
\n" ); document.write( "\n" ); document.write( "let the return trip take x hours\r
\n" ); document.write( "\n" ); document.write( "upstream will take x+1.5 hours\r
\n" ); document.write( "\n" ); document.write( "distance upstream = 2(x+1.5)\r
\n" ); document.write( "\n" ); document.write( "distance down stream = 3x\r
\n" ); document.write( "\n" ); document.write( "the distance is the same both ways\r
\n" ); document.write( "\n" ); document.write( "2(x+1.5)= 3x\r
\n" ); document.write( "\n" ); document.write( "2x+3=3x\r
\n" ); document.write( "\n" ); document.write( "3x-2x=3\r
\n" ); document.write( "\n" ); document.write( "x=3 down stream time\r
\n" ); document.write( "\n" ); document.write( "up stream will be 3+1.5 hours =4.5 hours\r
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