document.write( "Question 34126: A total of $15,000 is deposited into two simple interest accounts. The annual interest rate in one account is 14% and annual interest rate in the second account is 10%. How much must be invested into each account to earn $1740 in interest? \n" ); document.write( "
Algebra.Com's Answer #20497 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "INVESTMENT CLUBS: Part of $8000.00 was invested by an investment club at 10% interest and the rest at 12%. If the annual income from these investments is $900.00, how much was invested at each rate?
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\n" ); document.write( "1 solutions
\n" ); document.write( "Answer 20494 by venugopalramana(1483) About Me on 2006-04-19 06:55:45 (Show Source):
\n" ); document.write( "Part of $8000.00 was invested by an investment club at 10% interest
\n" ); document.write( "LET THIS INVESTMENT BE X...SO INTERST ON THIS IS..I=PNR/100=X*1*10/100=10X/100
\n" ); document.write( "and the rest at 12%.
\n" ); document.write( "REST OF THE MONEY IS (8000-X)...SO INTEREST ON THIS IS =(8000-X)*1*12/100
\n" ); document.write( "If the annual income from these investments is $900.00, how much was invested at each rate?
\n" ); document.write( "TOTAL INCOME =10X/100 + (8000-X)*12/10=900
\n" ); document.write( "(10X+96000-12X)/100=900
\n" ); document.write( "-2X+96000=90000
\n" ); document.write( "2X=96000-90000=6000
\n" ); document.write( "X=3000
\n" ); document.write( "HENCE 3000 IS INVESTED AT 10% AND REST 5000 INVESTED AT 12%
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