document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282235>Question 282235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> logv5 (3x-10)-3logv5 4=2\r<BR>\n" );
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document.write( "the \"v\" means sub and the 4 is after the sub5 not 54<BR>\n" );
document.write( "im having a lot of trouble and i could really use someones help :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204956 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.) logv5 (3x-10)-3logv5 4 = 2 \r<BR>\n" );
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document.write( "Using two laws of logs:\r<BR>\n" );
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document.write( "log a^b = b*log a  and<BR>\n" );
document.write( "log (a- b) = log a - log b\r<BR>\n" );
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document.write( "We have from 1.):\r<BR>\n" );
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document.write( "logv5 (3x-10) - logv5 4^3 = 2   (note that 4^3 = 64)\r<BR>\n" );
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document.write( "logv5 (3x-10)/64 = 2\r<BR>\n" );
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document.write( "By definition of a logv5 we have:\r<BR>\n" );
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document.write( "(3x-10)/64 = 5^2\r<BR>\n" );
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document.write( "3x-10 = 25*64\r<BR>\n" );
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document.write( "Solve the above for x.  </SPAN>\n" );
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