document.write( "Question 34156: Help me with this in a hurry please? I need it explained all problems algebraically please? \r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "INVESTMENT CLUBS: Part of $8000.00 was invested by an investment club at 10% interest and the rest at 12%. If the annual income from these investments is $900.00, how much was invested at each rate?\r
\n" );
document.write( "\n" );
document.write( "Thank you so much!! \n" );
document.write( "
Algebra.Com's Answer #20494 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Part of $8000.00 was invested by an investment club at 10% interest \n" ); document.write( "LET THIS INVESTMENT BE X...SO INTERST ON THIS IS..I=PNR/100=X*1*10/100=10X/100 \n" ); document.write( " and the rest at 12%. \n" ); document.write( "REST OF THE MONEY IS (8000-X)...SO INTEREST ON THIS IS =(8000-X)*1*12/100 \n" ); document.write( " If the annual income from these investments is $900.00, how much was invested at each rate? \n" ); document.write( "TOTAL INCOME =10X/100 + (8000-X)*12/10=900 \n" ); document.write( "(10X+96000-12X)/100=900 \n" ); document.write( "-2X+96000=90000 \n" ); document.write( "2X=96000-90000=6000 \n" ); document.write( "X=3000 \n" ); document.write( "HENCE 3000 IS INVESTED AT 10% AND REST 5000 INVESTED AT 12% \n" ); document.write( " |