document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34182>Question 34182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to mix a 75% acid solution with a 35% acid solution to produxe 400 ml of a 50% acid solution. How many ml of each solution should he use? Could someone show me how to do this problem? Thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20490 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist mixes two solutions. Solution A is 24% acid (the rest is water), and solution B is 41% acid. Some of each of the solutions are mixed to produce 50 gallons of a solution that is 31% acid. Find the difference between the quantity of solution A and the quantity of solution B used. Write your answer as a simplified fraction.<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 20212 by venugopalramana(1473) About Me  on 2006-04-17 05:43:48 (Show Source):<BR>\n" );
document.write( "Mixture_Word_Problems/30725: How many gallons of pure alcohol solution should be added to 63 gal of 32% alcohol solution to make a 37% solution? Thank you.<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 17458 by venugopalramana(1167) About Me on 2006-03-19 22:24:14 (Show Source):<BR>\n" );
document.write( "PLEASE SEE THE FOLLOWING EXAMPLE AND TRY.IF STILL IN DIFFICULTY,PLEASE COME BACK<BR>\n" );
document.write( "PLEASE HELP ASAP: Ziggy's famous yogurt blends regular yogurt that is 3% fat with its no fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of regular and how many pounds of non-fat yogurt should be mixed to obtain 60 pounds of lowfat yogurt.<BR>\n" );
document.write( "PLEASE HELP ASAP. thank you<BR>\n" );
document.write( "THESE ARE MATERIAL BALANCE PROBLEMS.THE PRINCIPLE IS TO APPLY<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS..<BR>\n" );
document.write( "THIS PRINCIPLE CAN BE APPLIED TO TOTAL MIXTURE AS A WHOLE AS WELL AS INDIVIDUAL COMPONENTS OF THE MIXTURE.LET US SEE THE APPLICATION USING YOUR PROBLEM.<BR>\n" );
document.write( "HERE THE MIXTURE COMPRISES 2 INPUTS-REGULAR YOGURT (RY) & NO FAT YOGURT (NFY)<BR>\n" );
document.write( "AND ONE OUT PUT-LOW FAT YOGURT (LFY).THE COMPONENT OF IMPORTANCE IN THE MIXTURE IS FAT CONTENT.SO WE TAKE 2 BALANCES HERE ..ONE FOR THE TOTAL MIXTURE AND ANOTHER FOR COMPONENT OF FAT IN THE MIXTURE.<BR>\n" );
document.write( "I..TOTAL BALANCE...<BR>\n" );
document.write( "INPUTS<BR>\n" );
document.write( "1.QTY.OF.RY=X POUNDS<BR>\n" );
document.write( "2.QTY OF NFY=Y POUNDS<BR>\n" );
document.write( "OUT PUT<BR>\n" );
document.write( "1.QTY.OF LFY=60 POUNDS<BR>\n" );
document.write( "SO APPLYING<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET<BR>\n" );
document.write( "X+Y=60.............................I<BR>\n" );
document.write( "II..COMPONENT BALANCE..HERE IT IS FAT .<BR>\n" );
document.write( "INPUTS<BR>\n" );
document.write( "1.QTY.OF FAT IN RY=X*3/100=3X/100 POUNDS<BR>\n" );
document.write( "2.QTY OF FAT IN NFY=Y*0/100=0 POUNDS<BR>\n" );
document.write( "OUT PUT<BR>\n" );
document.write( "1.QTY.OF FAT IN LFY=60*1/100=60/100 POUNDS<BR>\n" );
document.write( "SO APPLYING<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET<BR>\n" );
document.write( "3X/100 + 0=60/100.............................II<BR>\n" );
document.write( "3X=60<BR>\n" );
document.write( "X=20 POUNDS. OF REGULAR YOGURT<BR>\n" );
document.write( "Y=60-20=40 POUNDS OF NO FAT YOGURT.<BR>\n" );
document.write( "Mixture_Word_Problems/30727: How many gallons of 16% alcohol solution should be added to 30 gal of a 45% alcohol solution to make a 21% solution? Please help me set this up.<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 17453 by venugopalramana(1167) About Me on 2006-03-19 21:54:56 (Show Source):<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK<BR>\n" );
document.write( "PLEASE HELP ASAP: Ziggy's famous yogurt blends regular yogurt that is 3% fat with its no fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of regular and how many pounds of non-fat yogurt should be mixed to obtain 60 pounds of lowfat yogurt.<BR>\n" );
document.write( "PLEASE HELP ASAP. thank you<BR>\n" );
document.write( "THESE ARE MATERIAL BALANCE PROBLEMS.THE PRINCIPLE IS TO APPLY<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS..<BR>\n" );
document.write( "THIS PRINCIPLE CAN BE APPLIED TO TOTAL MIXTURE AS A WHOLE AS WELL AS INDIVIDUAL COMPONENTS OF THE MIXTURE.LET US SEE THE APPLICATION USING YOUR PROBLEM.<BR>\n" );
document.write( "HERE THE MIXTURE COMPRISES 2 INPUTS-REGULAR YOGURT (RY) & NO FAT YOGURT (NFY)<BR>\n" );
document.write( "AND ONE OUT PUT-LOW FAT YOGURT (LFY).THE COMPONENT OF IMPORTANCE IN THE MIXTURE IS FAT CONTENT.SO WE TAKE 2 BALANCES HERE ..ONE FOR THE TOTAL MIXTURE AND ANOTHER FOR COMPONENT OF FAT IN THE MIXTURE.<BR>\n" );
document.write( "I..TOTAL BALANCE...<BR>\n" );
document.write( "INPUTS<BR>\n" );
document.write( "1.QTY.OF.RY=X POUNDS<BR>\n" );
document.write( "2.QTY OF NFY=Y POUNDS<BR>\n" );
document.write( "OUT PUT<BR>\n" );
document.write( "1.QTY.OF LFY=60 POUNDS<BR>\n" );
document.write( "SO APPLYING<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET<BR>\n" );
document.write( "X+Y=60.............................I<BR>\n" );
document.write( "II..COMPONENT BALANCE..HERE IT IS FAT .<BR>\n" );
document.write( "INPUTS<BR>\n" );
document.write( "1.QTY.OF FAT IN RY=X*3/100=3X/100 POUNDS<BR>\n" );
document.write( "2.QTY OF FAT IN NFY=Y*0/100=0 POUNDS<BR>\n" );
document.write( "OUT PUT<BR>\n" );
document.write( "1.QTY.OF FAT IN LFY=60*1/100=60/100 POUNDS<BR>\n" );
document.write( "SO APPLYING<BR>\n" );
document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET<BR>\n" );
document.write( "3X/100 + 0=60/100.............................II<BR>\n" );
document.write( "3X=60<BR>\n" );
document.write( "X=20 POUNDS. OF REGULAR YOGURT<BR>\n" );
document.write( "Y=60-20=40 POUNDS OF NO FAT YOGURT.<BR>\n" );
document.write( "Mixture_Word_Problems/30587: The amount (by weight) of gold, silver and lead in three alloys of these metals are in ratios:<BR>\n" );
document.write( "4:3:2 - Alloy 1<BR>\n" );
document.write( "3:5:1 - Alloy 2<BR>\n" );
document.write( "2:2:5 - Alloy 3<BR>\n" );
document.write( "It is desired to make a fourth alloy containing equal amounts of gold, silver and lead. How many grams each alloy should be used for every 10 grams of the new alloy?<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 17262 by venugopalramana(1167) About Me on 2006-03-18 04:34:35 (Show Source):<BR>\n" );
document.write( "The amount (by weight) of gold, silver and lead in three alloys of these metals are in ratios:<BR>\n" );
document.write( "4:3:2 - Alloy 1<BR>\n" );
document.write( "3:5:1 - Alloy 2<BR>\n" );
document.write( "2:2:5 - Alloy 3<BR>\n" );
document.write( "It is desired to make a fourth alloy containing equal amounts of gold, silver and lead. How many grams each alloy should be used for every 10 grams of the new alloy?<BR>\n" );
document.write( "LET X GMS OF ALLOY1 ,Y GMS OF ALLOY2 AND 10-X-Y GMS OF ALLOY3 BE USED TO GET<BR>\n" );
document.write( "X+Y+10-X-Y=10 GMS OF ALLOY 4<BR>\n" );
document.write( "SO.................GOLD..............SIVER............LEAD IN THE MIX IS GIVEN BY<BR>\n" );
document.write( "X GMS A1...........4X/9..............3X/9..........2X/9<BR>\n" );
document.write( "Y GMS A2...........3Y/9..............5Y/9...........Y/9....<BR>\n" );
document.write( "10-X-Y GMS A3....(20-2X-2Y)/9 ......(20-2X-2Y)/9...(50-5X-5Y)/9<BR>\n" );
document.write( "-------------------------------------------------------------------------------<BR>\n" );
document.write( "10 GMS A4.......(20+2X+Y)/9........(20+X+3Y)/9.....(50-3X-4Y)/9<BR>\n" );
document.write( "THESE ARE ALL EQUAL...HENCE<BR>\n" );
document.write( "20+2X+Y = 20+X+3Y...OR......................X-2Y=0..............I<BR>\n" );
document.write( "20+2X+Y = 50-3X-4Y...OR...5X+5Y=30....OR....X+Y=6......II<BR>\n" );
document.write( "EQN.II - EQN I...GIVES<BR>\n" );
document.write( "X+Y-X+2Y=6......OR 3Y=6.....Y=2<BR>\n" );
document.write( "SO X=6-Y=6-2=4<BR>\n" );
document.write( "Z=10-4-2=4...<BR>\n" );
document.write( "HENCE 4 GMS OF A1,2 GMS OF A2 AND 4 GMS OF A3 ARE TO BE ADDED TO GET 10 GMS OF A4.<BR>\n" );
document.write( "Money_Word_Problems/29402: The nut store sells walnuts for 4.00 a pound and cashews for 7.00 a pound how many pounds of cashews should be mixed with 10 pounds of walnuts to obtain a mixture that sells for 5.50 a pound?<BR>\n" );
document.write( "1 solutions<BR>\n" );
document.write( "Answer 16262 by venugopalramana(1088) About Me on 2006-03-07 05:47:32 (Show Source):<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE WHICH WILL HELP YOU TO GET AN INSIGHT INTO THESE PROBLEMS AND THE METHOD OF APPROACH TO SOLVE THEM<BR>\n" );
document.write( "--------------------------------------------------------------------------<BR>\n" );
document.write( "How much pure alcohol must a nurse add to 8cc of a 70% solution to strengthen it to a 90% solution? Just need to know if this is right and if not what is right.<BR>\n" );
document.write( ".90(8)+ 0(x) = .70(x+8)....NO ...FIRST WRITE DOWN WHAT IS X?I THINK X IS QTY.OF<BR>\n" );
document.write( "PURE ALCOHOL TO BE ADDED TO 8 CC OF 70% ALCOHOL TO GET X+8 CC OF 90% SOLUTION.SO THE EQN. SHOULD BE X*100/100+8*70/100=(X+8)*90/100<BR>\n" );
document.write( "7.2 = .70x+5.6.....X+5.6=0.9(X+8)<BR>\n" );
document.write( "1.6 = 70x.......X-0.9X=7.2-5.6=1.6<BR>\n" );
document.write( "2.29c = x.......0.1X=1.6<BR>\n" );
document.write( "..................OR X=1.6/0.1=16 CC.<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE WHICH WILL HELP YOU TO GET AN INSIGHT INTO THESE PROBLEMS AND THE METHOD OF APPROACH TO SOLVE THEM<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );