document.write( "Question 4506: Change to exponential form\r
\n" ); document.write( "\n" ); document.write( "log 10^x + log 10 (x + 15) = 2\r
\n" ); document.write( "\n" ); document.write( "\"log+%2810%2C+x%29+%2B+log+%2810%2C+%28x%2B15%29%29+=+2\"
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Algebra.Com's Answer #2049 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"log+%2810%2C+x%29+%2B+log+%2810%2C+%28x%2B15%29%29+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "By the first law of logarithms, log M + log N = log MN
\n" ); document.write( "\"log+%2810%2C+x%28x%2B15%29%29+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "Convert from logarithmic notation to exponential form by writing this as
\n" ); document.write( "\"10%5E2+=+x%28x%2B15%29\"
\n" ); document.write( "\"100+=+x%5E2+%2B+15x\"\r
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\n" ); document.write( "\n" ); document.write( "Set equal to zero:
\n" ); document.write( "\"0+=+x%5E2+%2B+15x+-+100\"\r
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\n" ); document.write( "\n" ); document.write( "Factor the trinomial:\r
\n" ); document.write( "\n" ); document.write( "\"0+=+%28x+%2B+20%29%28x+-+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore x = -20 or x = 5. \r
\n" ); document.write( "\n" ); document.write( "However, if x = -20, then the original equation results in log (-20) + log (-5) which is not a real number, so this answer must be rejected.\r
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\n" ); document.write( "\n" ); document.write( "Final answer is x = 5 the only possible solution.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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