document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282194>Question 282194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular field is 12cm longer than it is wide.  Its perimeter is 52 cms<BR>\n" );
document.write( "find the width???? how i do this </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204899 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = P = 2L + 2W<BR>\n" );
document.write( "P = 52<BR>\n" );
document.write( "L = W+12  :: Length is 12 more than width, so you'd have to add 12 to L to make it equal.<BR>\n" );
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document.write( "2L + 2W = 2(L+W)<BR>\n" );
document.write( "2(L+W) = 52<BR>\n" );
document.write( "L+W = 26<BR>\n" );
document.write( "(W+12)+W = 26<BR>\n" );
document.write( "2W+12=26<BR>\n" );
document.write( "2W = 14<BR>\n" );
document.write( "W = 7<BR>\n" );
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document.write( "L=W+12<BR>\n" );
document.write( "L=7+12<BR>\n" );
document.write( "L=19<BR>\n" );
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document.write( "Check perimeter to be sure it is 52.<BR>\n" );
document.write( "2(7+19) = 2(26) = 52<BR>\n" );
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document.write( "State answer:<BR>\n" );
document.write( "W = 7<BR>\n" );
document.write( "L = 19<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Done </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );