document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34184>Question 34184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the parabola: y=x^2-6x+5<BR>\n" );
document.write( "Complete the Square<BR>\n" );
document.write( "Give the Vertex<BR>\n" );
document.write( "Give the x- and y-intercepts<BR>\n" );
document.write( "Graph the parabola\r<BR>\n" );
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document.write( "Could someone please help me with this problem?  Thank you so very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20489 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING AND TRY<BR>\n" );
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document.write( "Equations/30056: I need to determine the following for these two problems :HOW MANY X-INTERCEPTS THE PARABOLA HAS, and WHETER ITS VERTEX LIES ABOVE OR BELOW OR ON THE X-AXIS.						<BR>\n" );
document.write( "1.problem						<BR>\n" );
document.write( "y=x^2-5x+6						<BR>\n" );
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document.write( "2.problem						<BR>\n" );
document.write( "y=-x^2+2x-1						<BR>\n" );
document.write( "1 solutions						<BR>\n" );
document.write( "Answer 16805 by venugopalramana(1167) About Me  on 2006-03-13 10:41:52 (Show Source):						<BR>\n" );
document.write( "I need to determine the following for these two problems :HOW MANY X-INTERCEPTS THE PARABOLA HAS, and WHETER ITS VERTEX LIES ABOVE OR BELOW OR ON THE X-AXIS.						<BR>\n" );
document.write( "1.problem						<BR>\n" );
document.write( "y=x^2-5x+6						<BR>\n" );
document.write( "PUT Y=0 AND SOLVE FOR X TO GET X INTERCEPTS.						<BR>\n" );
document.write( "X^2-5X+6=0=X^2-2X-3X+6=0=X(X-2)-3(X-2)=0=(X-2)(X-3)=0....X=2 AND 3...						<BR>\n" );
document.write( "SO THE X INTERCEPTS ARE AT X = 2 AND X = 3						<BR>\n" );
document.write( "Y=X^2-5X+6={X^2-2*X*5/2+(5/2)^2}-(5/2)^2+6 =(X-2.5)^2 - 0.25						<BR>\n" );
document.write( "SO THE VERTEX IS AT X=2.5 AND Y=-0.25...THAT IS BELOW X AXIS						<BR>\n" );
document.write( "2.problem						<BR>\n" );
document.write( "y=-x^2+2x-1						<BR>\n" );
document.write( "DOING THE SAME WAY WE GET						<BR>\n" );
document.write( "Y=-(X-1)^2=0 AND HENCE						<BR>\n" );
document.write( "X INTERCEPTS ARE X=1						<BR>\n" );
document.write( "AND VERTEX IS AT X=1 AND Y=0 SO THE VERTEX IS ON THE X AXIS.						<BR>\n" );
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document.write( "Coordinate-system/29860: I am working with parabolas. For this problem I need to						<BR>\n" );
document.write( "Complete the square						<BR>\n" );
document.write( "Give the Vertex						<BR>\n" );
document.write( "Give the Axis						<BR>\n" );
document.write( "Give the x-intercepts						<BR>\n" );
document.write( "Give the y-intercepts						<BR>\n" );
document.write( "Give a point symmetric to the y-intercept						<BR>\n" );
document.write( "Draw the graph						<BR>\n" );
document.write( "The problem is y=x^2-2x-3.						<BR>\n" );
document.write( "Can anyone help me solve this. I am working on it and would like to have something to check my answer with.						<BR>\n" );
document.write( "1 solutions						<BR>\n" );
document.write( "Answer 16624 by venugopalramana(1167) About Me  on 2006-03-11 07:58:25 (Show Source):						<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE WHICH IS ALMOST SAME AS YOUR PROBLEM AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK.						<BR>\n" );
document.write( "Y=X^2-2X-3=X^2-2*X*1+1^2-1-3=(X-1)^2-1-3=(X-1)^2-4=0						<BR>\n" );
document.write( "X INTERCEPT IS OBTAINED BY PUTTING Y=0....WE GET						<BR>\n" );
document.write( "X^2-2X-3=0=X^2-3X+X-3=X(X-3)+1(X-3)=(X-3)(X+1)=0...SO..X=3 OR -1...						<BR>\n" );
document.write( "Y INTERCEPT IS GOT BY PUTTING X =0...WE GET						<BR>\n" );
document.write( "Y=0-0-3=-3						<BR>\n" );
document.write( "SEE THE GRAPH BELOW ......						<BR>\n" );
document.write( "graph( 500, 500, -10, 20, -20, 20,x^2-2x-3 )						<BR>\n" );
document.write( "THE AXIS IS X=1 AS YOU CAN SEE FROM THE GRAPH						<BR>\n" );
document.write( "ONE POINT SYMMETRIC TO Y INTERCEPT??NO...SYMMETRIC TO AXIS IT IS......(-1,3)						<BR>\n" );
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document.write( "I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k.						<BR>\n" );
document.write( "MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE.						<BR>\n" );
document.write( "Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE						<BR>\n" );
document.write( "y=a(x-h)^2+k.						<BR>\n" );
document.write( "WE GET A=1 AND K=-16						<BR>\n" );
document.write( "I have to find the line of symmetry.						<BR>\n" );
document.write( "X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12						<BR>\n" );
document.write( "(h,k)=vertex I think you use complete the square technique.						<BR>\n" );
document.write( "YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX						<BR>\n" );
document.write( "THE GRAPH WILL LOOK LIKE THIS						<BR>\n" );
document.write( "graph( 500, 500, -10, 20, -20, 20, x^2-2x-15 )						<BR>\n" );
document.write( "Please help. thanks </SPAN>\n" );
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