document.write( "Question 281949: blake has a total of $1600 to invest in two accounts. One account earns 2% simple interest, and the othr account earns 9% simple interest. How much should be invested in both accounts to earn exactly $102 at the end of one year? \n" ); document.write( "
Algebra.Com's Answer #204812 by brucewill(101)\"\" \"About 
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Let x = the amount invested in the 2% account.
\n" ); document.write( "Then (1600-x) = the amount invested in the 9% account.\r
\n" ); document.write( "\n" ); document.write( "\".02x+%2B+.09%281600-x%29+=+102\" Multiply through by 100 to clear decimals
\n" ); document.write( "---
\n" ); document.write( "\"2x+%2B+9%281600-x%29+=+10200\"
\n" ); document.write( "---
\n" ); document.write( "\"2x+%2B+14400+-+9x+=+10200\" add 9x to both sides, and subtract 14400 from both sides
\n" ); document.write( "---
\n" ); document.write( "\"-7x+=+-4200\" divide both sides by -7
\n" ); document.write( "---
\n" ); document.write( "\"x+=+highlight%28600%29\"
\n" ); document.write( "---
\n" ); document.write( "amount at 2% $600; amount at 9% $1000. \r
\n" ); document.write( "\n" ); document.write( "$600 * 2% = $12
\n" ); document.write( "$1000 * 9% = $90
\n" ); document.write( "Total interest: $102.
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