document.write( "Question 281949: blake has a total of $1600 to invest in two accounts. One account earns 2% simple interest, and the othr account earns 9% simple interest. How much should be invested in both accounts to earn exactly $102 at the end of one year? \n" ); document.write( "
Algebra.Com's Answer #204812 by brucewill(101)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the amount invested in the 2% account. \n" ); document.write( "Then (1600-x) = the amount invested in the 9% account.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( "amount at 2% $600; amount at 9% $1000. \r \n" ); document.write( "\n" ); document.write( "$600 * 2% = $12 \n" ); document.write( "$1000 * 9% = $90 \n" ); document.write( "Total interest: $102. \n" ); document.write( " |