document.write( "Question 281964: find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers \n" ); document.write( "

Algebra.Com's Answer #204808 by brucewill(101) $\"\"$ $\"About$

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The three numbers would be x, x+2 and x+4.\r
\n" ); document.write( "\n" ); document.write( "3x is 3 times the first number
\n" ); document.write( "(x+2+x+4)-1 is one less than the sum of the second and third integers.\r
\n" ); document.write( "\n" ); document.write( " $\"3x+=+x%2B2%2Bx%2B4-1\"$
\n" ); document.write( " $\"3x+=+2x+%2B+5\"$
\n" ); document.write( " $\"x+=+highlight+%285%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Answer: 5, 7, 9.\r
\n" ); document.write( "\n" ); document.write( "Proof: 5*3 = 15
\n" ); document.write( "7+9-1 = 15\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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