document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281950>Question 281950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The peroid T (in seconds) of a simple pendulum as a function of its length,L (in feet) is given by  T(L)=2pi square root(L/32.2)\r<BR>\n" );
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document.write( "The question is to express the length,L as a function of the period T. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204786 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T(L)=2pi square root(L/32.2) <BR>\n" );
document.write( "The question is to express the length,L as a function of the period T.<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( "T(L) = 2pi*sqrt(L/32.2)<BR>\n" );
document.write( "sqrt(L/32.2) = T(L)/(2pi)<BR>\n" );
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document.write( "Square both sides to get:<BR>\n" );
document.write( "L/32.2 = [T(L)/(2pi)]^2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "L = 32.3[T/2pi]^2<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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