document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281841>Question 281841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 13. By which of the following number is 98765432 exactly divisible?<BR>\n" );
document.write( "A. 9<BR>\n" );
document.write( "B. 7<BR>\n" );
document.write( "C. 5<BR>\n" );
document.write( "D. 8<BR>\n" );
document.write( "E. 11\r<BR>\n" );
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document.write( "Hello!<BR>\n" );
document.write( "Can you please show me step by step how to solve the answer.<BR>\n" );
document.write( "Thank you<BR>\n" );
document.write( "Tania </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204755 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are indeed numerous ways to do this.\r<BR>\n" );
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document.write( "However, an easy way to do this (although not entirely concise!) is to factor 2's.\r<BR>\n" );
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document.write( "IE. We know that 2 will factor out as the number is even.\r<BR>\n" );
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document.write( "Secondly, we know another 2 will factor out as we will have 16 as the last two digits.\r<BR>\n" );
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document.write( "Thirdly, we know yet another 2 will factor out as we will have 58 as the last two digits.\r<BR>\n" );
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document.write( "hence, 2^3 is a factor. 2^3=8. hence 8|98765432.\r<BR>\n" );
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document.write( "In other words, 8u=98765432 gives u as an integer hence it is exactly divisible.\r<BR>\n" );
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document.write( "--- You could solve this using modular arithmetic and a few other ways, but I think this is the most intuitive. </SPAN>\n" );
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