document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281857>Question 281857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man was cycling south wards at a speed of 10 miles / hr when he met another man who was cycling west wards at the speed of 11 miles / hr. How far apart they would be after a period of 01 hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204723 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> after one hour they will be diagonally apart . Like the hypotenuse of a right triangle.\r<BR>\n" );
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document.write( "the legs will be 11 and 10 since after one hour they would have traveled 11 and 10 miles repectively\r<BR>\n" );
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document.write( "10^2+11^2= hyp^2\r<BR>\n" );
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document.write( "sqrt 221 = hypotenuse \r<BR>\n" );
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document.write( "= 14.866 miles.\r<BR>\n" );
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