document.write( "Question 281845: I had this mixture problem on a quiz and its really hard. If i'd pulled out 10 hairs for each time i tried again, i'd be bald. Can someone help me with it? It is a mixture problem which is:\r
\n" ); document.write( "\n" ); document.write( "One solution is 80% acid and another one is 30% acid. How much of each solution is needed to make a 200L solution that is 62% acid?\r
\n" ); document.write( "\n" ); document.write( "I really need help with this so someone please answer it please! Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #204720 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
One solution is 80% acid and another one is 30% acid. How much of each solution is needed to make a 200L solution that is 62% acid?
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\n" ); document.write( "Let x = amount of 80% acid
\n" ); document.write( "then
\n" ); document.write( "200-x = amount of 30% acid
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\n" ); document.write( "Our equation:
\n" ); document.write( ".80x + .30(200-x) = .62(200)
\n" ); document.write( ".80x + 60 - .30x = 124
\n" ); document.write( ".50x + 60 = 124
\n" ); document.write( ".50x = 64
\n" ); document.write( "x = 128 L (80% acid)
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\n" ); document.write( "30% acid:
\n" ); document.write( "200-x = 200-128 = 72 L (30% acid)\r
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