document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281765>Question 281765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The line passing through (-2,y) and (1,0) is perpendicular to line joining (3,3) and (-1,1). Find y. \r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204692 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the slope of first line be m1 and slope of second line be m2 then <BR>\n" );
document.write( "for both lines to be perpendicular to each other m1*m2 = -1\r<BR>\n" );
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document.write( "lets find m1 and m2\r<BR>\n" );
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document.write( "m1 = (0 - y) / [1 - (-2)] = -(y)/3<BR>\n" );
document.write( "m2 = (1 - 3) / (-1 - 3) = 2/4 = 1/2\r<BR>\n" );
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document.write( "m1*m2 = -1<BR>\n" );
document.write( "-(y)/3 * 1/2 = -1<BR>\n" );
document.write( "-(y)/6 = -1\r<BR>\n" );
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document.write( "y = 6 </SPAN>\n" );
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