document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281733>Question 281733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Farmer wants to buy cows, pigs and chickens. He has $100 and wants to buy total of 100 combined animals. Cows are $10. Pigs are $3. Chickens are $.50. How many of each animal should he buy to get 100 total animals for $100? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204677 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you know there are going to be a lot of chickens and few cows.<BR>\n" );
document.write( "w+p+n=100<BR>\n" );
document.write( "10w+3p+.5n=100\r<BR>\n" );
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document.write( "If there were all chickens he could buy 200 chickens<BR>\n" );
document.write( "If there were all cows he could by 10 cows<BR>\n" );
document.write( "If there were all pigs he could by 33 pigs and have a dollar left over.\r<BR>\n" );
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document.write( "So the numbers need to be between 0 and those upper limits.<BR>\n" );
document.write( "0 < w < 11<BR>\n" );
document.write( "0 < p < 34<BR>\n" );
document.write( "0 < n < 201<BR>\n" );
document.write( "chicken=n=94<BR>\n" );
document.write( "cow=w=5<BR>\n" );
document.write( "pig=p=1<BR>\n" );
document.write( "5*10+94*.5+1*3=100<BR>\n" );
document.write( "50+47+3=100<BR>\n" );
document.write( "94+5+1=100<BR>\n" );
document.write( " </SPAN>\n" );
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