document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281591>Question 281591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (-2x^6y^5)^3 evaluate expression for x = 1/3 and y = 3 . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204609 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-2x^6y^5)^3 When x = 1/3 and y = 3 <BR>\n" );
document.write( "[-2(1/3^6)(3^5)]^3<BR>\n" );
document.write( "[-2(1/729)(243)]^3<BR>\n" );
document.write( "[-2(243/729)]^3<BR>\n" );
document.write( "[-2*1/3]^3<BR>\n" );
document.write( "[-2/3]^3<BR>\n" );
document.write( "-8/27 ans. </SPAN>\n" );
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