document.write( "Question 281617: Find three consecutive odd integers for which three times the smallest is 15 less than the sum of the other two. \n" ); document.write( "
Algebra.Com's Answer #204601 by College Student(505)\"\" \"About 
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To find three odd consecutive integers, we can plot them as follows:\r
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\n" ); document.write( "\n" ); document.write( "x = first integer
\n" ); document.write( "x+2 = odd consecutive integer
\n" ); document.write( "x+4 = next odd consecutive integer\r
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\n" ); document.write( "\n" ); document.write( "Now, let's substitute these values according to the problem and solve for \"x\" to find the first integer.\r
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\n" ); document.write( "\n" ); document.write( "If three times the smallest is 15 less than the sum of the other two...
\n" ); document.write( "* Three times the smallest would equal to 3x.
\n" ); document.write( "* The word \"is\" means =.
\n" ); document.write( "* The sum of the other two would be (x+2) plus (x+4).
\n" ); document.write( "Therefore:\r
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\n" ); document.write( "\n" ); document.write( "\"3x=%28x%2B2%29%2B%28x%2B4%29-15\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x:\r
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\n" ); document.write( "\n" ); document.write( "\"3x=2x%2B2%2B4-15\"
\n" ); document.write( "\"3x=2x-9\"
\n" ); document.write( "\"3x-2x=-9\"
\n" ); document.write( "\"x=-9\"\r
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\n" ); document.write( "\n" ); document.write( "I'll let you find the other two odd consecutive integers.
\n" ); document.write( "You can check its validity by substituting the x for -9 in the original equation. Both sides of the equation must equal to each other to be true.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=%28x%2B2%29%2B%28x%2B4%29-15\"
\n" ); document.write( "\"3%28-9%29=%28-9%2B2%29%2B%28-9%2B4%29-15\"
\n" ); document.write( "\"-27=-27\" ... it checks!
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