document.write( "Question 281617: Find three consecutive odd integers for which three times the smallest is 15 less than the sum of the other two. \n" ); document.write( "
Algebra.Com's Answer #204601 by College Student(505)![]() ![]() You can put this solution on YOUR website! To find three odd consecutive integers, we can plot them as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = first integer \n" ); document.write( "x+2 = odd consecutive integer \n" ); document.write( "x+4 = next odd consecutive integer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, let's substitute these values according to the problem and solve for \"x\" to find the first integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If three times the smallest is 15 less than the sum of the other two... \n" ); document.write( "* Three times the smallest would equal to 3x. \n" ); document.write( "* The word \"is\" means =. \n" ); document.write( "* The sum of the other two would be (x+2) plus (x+4). \n" ); document.write( "Therefore:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now solve for x:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you find the other two odd consecutive integers. \n" ); document.write( "You can check its validity by substituting the x for -9 in the original equation. Both sides of the equation must equal to each other to be true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |