document.write( "Question 281617: Find three consecutive odd integers for which three times the smallest is 15 less than the sum of the other two. \n" ); document.write( "

Algebra.Com's Answer #204598 by Mathematicians(84) $\"\"$ $\"About$

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Here is your question, we need to translate it into equations:\r
\n" ); document.write( "\n" ); document.write( "\"Find three consecutive odd integers for which three times the smallest is 15 less than the sum of the other two.\"\r
\n" ); document.write( "\n" ); document.write( "let x = smallest odd integer
\n" ); document.write( "then x + 2 = next odd integer
\n" ); document.write( "then x + 4 = second to next odd integer\r
\n" ); document.write( "\n" ); document.write( " $\"+3x+=+%28x+%2B+2%29+%2B+%28x+%2B+4%29+-+15\"$ \r
\n" ); document.write( "\n" ); document.write( "The above equation says 3 times the smallest is equal to the sum of the other two less than 15.\r
\n" ); document.write( "\n" ); document.write( " $\"3x++=+2x++-+9+\"$ combine like terms
\n" ); document.write( " $\"x+=+-9\"$ solving for x\r
\n" ); document.write( "\n" ); document.write( "which is true because 3 times -9 is -27 which is 15 less than -12 which is the sum of -7 and -5 \n" ); document.write( "

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