document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281609>Question 281609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ordered pairs are for a direct variation. Find the missing value. I know that the direct variation form is y=kx but I'm not sure how to use it to find the missing value of the ordered pair.<BR>\n" );
document.write( "(-2,8) and (x,12) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204586 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=kx<BR>\n" );
document.write( "plug in the first ordered pair (-2,8) to find k<BR>\n" );
document.write( "8=k*(-2)<BR>\n" );
document.write( "-4=k<BR>\n" );
document.write( "y=-4x<BR>\n" );
document.write( "now plug in the y of (x,12) to find x<BR>\n" );
document.write( "12=-4x<BR>\n" );
document.write( "-3=x<BR>\n" );
document.write( "(-3,12) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );