document.write( "Question 281596: Factor as completely as possible.
\n" ); document.write( "a) $\"x%5E3-4x\"$
\n" ); document.write( "b) $\"xy-x%2B8y-8\"$
\n" ); document.write( "c) $\"x%5E3%2Bx%5E2-90x\"$ \r
\n" ); document.write( "\n" ); document.write( "Hello! You dont have to do all three of these (unless you want too; go ahead and knock yourself out ;) ) What I wanted to know was if someone could please explain to me how I would factor these as completely as possible?
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #204578 by JBarnum(2146) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"x%5E3-4x\"$
\n" ); document.write( "for this one when u look at it theres a x in both variables so the gcf is x
\n" ); document.write( " $\"x%28x%5E2-4%29\"$ whats left is a perfect square inside the brackets so you can factor further, i sugest getting familiar with what squars look like to make it easier for u to factor, otherwise u will need to use the quadratic formula.(Ex: $\"x%5E2-36\"$ 6's, $\"x%5E2-49\"$ 7's, $\"x%5E2-144\"$ 12's)
\n" ); document.write( " $\"highlight%28x%28x-2%29%28x%2B2%29%29\"$ this would be completly factored
\n" ); document.write( "

\n" ); document.write( " $\"%28xy-x%29%2B%288y-8%29\"$ use group factoring
\n" ); document.write( " $\"x%28y-1%29%2B8%28y-1%29\"$ factor x and 8 out
\n" ); document.write( " $\"highlight%28%28x%2B8%29%28y-1%29%29\"$ add them together, completely factored
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\n" ); document.write( " $\"x%5E3%2Bx%5E2-90x\"$ same as first one GCF=x
\n" ); document.write( " $\"x%28x%5E2%2Bx-90%29\"$ find 2 numbers multiply to get -90 and add to get 1. -9 and +10. if u cant figure how to do this then use quadratic formula.
\n" ); document.write( " $\"highlight%28x%28x%2B10%29%28x-9%29%29\"$ this is completely factored \n" ); document.write( "

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