document.write( "Question 34165: I have a problem that I can't figure out. \r
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document.write( "Joe has a collection of nickels and dimes that is worth $7.40. If the number of dimes were doubled and the number of nickels were increased by 20, the value of the coins would be $13.20. How many dimes does he have?\r
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document.write( "I have been trying to work this but can't seem to get it set up right.
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #20457 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the number of nickels be x \n" ); document.write( "Let the number of dimes be y \n" ); document.write( "Equation (1): \n" ); document.write( "10y+5x=740 \n" ); document.write( "x=148-2y (subsitution) \n" ); document.write( "2(10y)+5(x+20)=1320 \n" ); document.write( "20y+5x+100=1320 \n" ); document.write( "20y+5(148-2y)+100=1320 \n" ); document.write( "20y+740-10y+100=1320 \n" ); document.write( "10y=480 \n" ); document.write( "y=48 \n" ); document.write( "x=148-2(48) \n" ); document.write( "y=52 \n" ); document.write( "Hence, there are 48 nickels and 52 dimes. \n" ); document.write( "Paul. \n" ); document.write( " |