document.write( "Question 34165: I have a problem that I can't figure out. \r
\n" ); document.write( "\n" ); document.write( "Joe has a collection of nickels and dimes that is worth $7.40. If the number of dimes were doubled and the number of nickels were increased by 20, the value of the coins would be $13.20. How many dimes does he have?\r
\n" ); document.write( "\n" ); document.write( "I have been trying to work this but can't seem to get it set up right.
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #20457 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
Let the number of nickels be x
\n" ); document.write( "Let the number of dimes be y
\n" ); document.write( "Equation (1):
\n" ); document.write( "10y+5x=740
\n" ); document.write( "x=148-2y (subsitution)
\n" ); document.write( "2(10y)+5(x+20)=1320
\n" ); document.write( "20y+5x+100=1320
\n" ); document.write( "20y+5(148-2y)+100=1320
\n" ); document.write( "20y+740-10y+100=1320
\n" ); document.write( "10y=480
\n" ); document.write( "y=48
\n" ); document.write( "x=148-2(48)
\n" ); document.write( "y=52
\n" ); document.write( "Hence, there are 48 nickels and 52 dimes.
\n" ); document.write( "Paul.
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