document.write( "Question 34056: Can you help me solve
\n" ); document.write( "A car travels 180 mi. A second car, traveling 15 mi/hr faster than the first car, makes the same trip in 1 h less time. find the speed of each car. \n" ); document.write( "

Algebra.Com's Answer #20455 by Paul(988) $\"\"$ $\"About$

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The second car travels at 15+x
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document.write( "THe first car travels at x
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document.write( "Since its 1 hours less it's
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document.write( "d/(x)=d/(x+15)+1
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document.write( "and d=180
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document.write( "Equation:
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document.write( "Cross mutliply:
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document.write( "180[(15+x)-(x)]=(x+15)(x)
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document.write( "a=1, b=15, c=-2700 in quardatic formula:
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document.write( "simplfy:
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document.write( "x=45 or x=-60
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document.write( "remove the negative and x=45.
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document.write( "Hence, the speed of the first car was 45mph and the second car was 60mph.
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document.write( "Paul. \n" );
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