document.write( "Question 281573: how do you solve
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document.write( "ln (2x+3)+ln(x-6)-2 ln x =0
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document.write( "Thank you soooo much
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Algebra.Com's Answer #204548 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Applying \"log rules\": \n" ); document.write( "ln (2x+3)+ln(x-6)-2 ln x =0 \n" ); document.write( "ln (2x+3)+ln(x-6)- ln x^2 =0 \n" ); document.write( "ln (2x+3)(x-6)- ln x^2 =0 \n" ); document.write( "ln [(2x+3)(x-6)]/x^2 =0 \n" ); document.write( "[(2x+3)(x-6)]/x^2 = e^0 \n" ); document.write( "[(2x+3)(x-6)]/x^2 = 1 \n" ); document.write( "(2x+3)(x-6) = x^2 \n" ); document.write( "2x^2-12x+3x-18 = x^2 \n" ); document.write( "2x^2-9x-18 = x^2 \n" ); document.write( "x^2-9x-18 = 0 \n" ); document.write( "Solve by applying the quadratic equation. This results in: \n" ); document.write( "x = {10.685, -1.685} \n" ); document.write( "But, we can toss out the negative solution since this results in taking a ln of a negative number. This is an extraneous solution -- toss it out. Leaving our solution as: \n" ); document.write( "x = 10.685 \n" ); document.write( ". \n" ); document.write( "Details of quadratic equation follows: \n" ); document.write( "
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