document.write( "Question 281545: The problem is: The mean contents of bottles of a certain brand of soft drink is 310 ml. with a standard deviation of 5 ml.
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document.write( "a) What percentage of bottles would contain betwen 300 and 310 ml of contents?
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document.write( "b) What percentage of bottles would contain at least 304 ml of contents?
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document.write( "c) What is the probability of a bottle containing less than 300 ml of content? \n" );
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Algebra.Com's Answer #204534 by Mathematicians(84)![]() ![]() You can put this solution on YOUR website! Unfortunately I do not have a Z table, not to mention different Z tables calculate things differently. with me and it has been ages since I took statistics, but this should be the correct way to solve this problem.\r \n" ); document.write( "\n" ); document.write( "You have the formula:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a) our data is 300 and 310 and we want it in between. Well, we know 310 is the mean so that is when z = 0. We do not need to check this, we need to check 300.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Depending on your Z table, Z = -2 should correspond with some decimal. That is your answer.\r \n" ); document.write( "\n" ); document.write( "b) with this one, you want to calculate z > 304. Once again, depending how your Z table looks at it, you will either have to do 1 - P(x=304) or .5 + p(x = 304)\r \n" ); document.write( "\n" ); document.write( "We can begin calculating Z:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I can't really tell you how your Z table calculates probability because I have had two different Z tables in a couple different classes a few years ago. \n" ); document.write( " |