document.write( "Question 281519: How do I solve the sum of twice a number and its square is 143? I can write out the equation, but I don't know the answer. \n" ); document.write( "
Algebra.Com's Answer #204516 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
\"2x%2Bx%5E2=143\" this is a quadratic equation , set it equal to 0
\n" ); document.write( "\"x%5E2%2B2x-143=0\" a=1 b=2 c=-143
\n" ); document.write( "\"-b%2B%28%28sqrt%28b%5E2-4ac%29%29%2F2a%29\"\"-b-%28%28sqrt%28b%5E2-4ac%29%29%2F2a%29\"
\n" ); document.write( "\"-2%2B%28%28sqrt%282%5E2-4%2A1%2A-143%29%29%2F%282%2A1%29%29\" \"-2-%28%28sqrt%282%5E2-4%2A1%2A-143%29%29%2F%282%2A1%29%29\"
\n" ); document.write( "\"-2%2B%28%28sqrt%284%2B572%29%29%2F2%29\" \"-2-%28%28sqrt%284%2B572%29%29%2F2%29\"
\n" ); document.write( "\"-2%2B%28%28sqrt%28576%29%29%2F2%29\" \"-2-%28%28sqrt%28576%29%29%2F2%29\"
\n" ); document.write( "\"-2%2B%2824%2F2%29\" \"-2-%2824%2F2%29\"
\n" ); document.write( "\"-2%2B%2812%29\" \"-2-%2812%29\"
\n" ); document.write( "x=\"highlight%2810%29\", \"highlight%28-14%29\"
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