document.write( "Question 281519: How do I solve the sum of twice a number and its square is 143? I can write out the equation, but I don't know the answer. \n" ); document.write( "
Algebra.Com's Answer #204512 by Mathematicians(84)\"\" \"About 
You can put this solution on YOUR website!
Judging by your question, writing out the equation is:\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+x%5E2+=+143\"\r
\n" ); document.write( "\n" ); document.write( "In order to solve this equation, you need to get everything on one side:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+2x+-+143+=+0\"\r
\n" ); document.write( "\n" ); document.write( "We need to find two numbers that add up to be positive 2 and multiply to be 143. 143 is 13 * 11 which is a coincidence because those are two apart from each other.\r
\n" ); document.write( "\n" ); document.write( "We get\r
\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+13%29%28x+-+11%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Using zero product principle, we know that\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+11%29+=+0\"
\n" ); document.write( "\"highlight+%28x+=+11%29\"\r
\n" ); document.write( "\n" ); document.write( "or \r
\n" ); document.write( "\n" ); document.write( "\"%28x+%2B+13%29+=+0\"
\n" ); document.write( "\"highlight+%28x+=+-13%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Both of these are your answers! See ya around!
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