document.write( "Question 281420: the lenght of a regular lot is 6 yards longer than twice the width.if the perimeter is 288 yards,what are the lots of dimensions
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Algebra.Com's Answer #204500 by brucewill(101)\"\" \"About 
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Let x = width
\n" ); document.write( "Then 2x + 6 = length\r
\n" ); document.write( "\n" ); document.write( "We need 2 widths, and 2 lengths to equal 288.\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+2%282x+%2B+6%29+=+288\"
\n" ); document.write( "\"2x+%2B+4x+%2B+12+=+288\"
\n" ); document.write( "\"6x+=+276\"
\n" ); document.write( "\"x+=+highlight%2846%29\" width
\n" ); document.write( "\"2x+%2B+6+=+highlight%2898%29\" length\r
\n" ); document.write( "\n" ); document.write( "Prove: 46+98+46+98=288.
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