document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=279762>Question 279762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 a.m. and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in. Her father immediately jumped on his scooter to try and track her down and tell her the good news.\r<BR>\n" );
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document.write( "Riding at a breezy 15 miles per hour, after how many hours on the scooter will her father catch up to her? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204462 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What no cell phone?!<BR>\n" );
document.write( "The equestrian rode two hours more than the father so that will be x+2 and the father x<BR>\n" );
document.write( "10*(2+x)=15x<BR>\n" );
document.write( "solve for x<BR>\n" );
document.write( "add x to 12:00 \r<BR>\n" );
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document.write( "or we could say that she went 20 miles in those two hours 2*10<BR>\n" );
document.write( "10x+20=15x<BR>\n" );
document.write( "still add x to 12:00<BR>\n" );
document.write( " </SPAN>\n" );
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