document.write( "Question 281440: The side of one square is 5 units longer than that of another square. Their areas differ by 105 square units. The lengths of their sides are:\r
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document.write( "(A) 5 and 10 units (B) 7.5 and 12.5 units (C) 8 and 13 units
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document.write( "(D) 15 and 20 units (E) none of these\r
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Algebra.Com's Answer #204448 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! The side of one square is 5 units longer than that of another square. Their areas differ by 105 square units. The lengths of their sides are: \n" ); document.write( "(A) 5 and 10 units (B) 7.5 and 12.5 units (C) 8 and 13 units \n" ); document.write( "(D) 15 and 20 units (E) none of these \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the length of the sides of the smaller square. Then x+5 is the length of the sides of the larger square. Then the areas of the squares are x^2 and (x+5)^2 respectively.\r \n" ); document.write( "\n" ); document.write( "So we have:\r \n" ); document.write( "\n" ); document.write( "(x+5)^2 - x^2 = 105\r \n" ); document.write( "\n" ); document.write( "Expanding using FOIL gives us:\r \n" ); document.write( "\n" ); document.write( "x^2 + 10x + 25 - x^2 = 105\r \n" ); document.write( "\n" ); document.write( "10x + 25 = 105\r \n" ); document.write( "\n" ); document.write( "Solve for x and calculate x+5. \n" ); document.write( " |