document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=281439>Question 281439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a constant rate, the number of minutes before Jessica laps Sharon is:\r<BR>\n" );
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document.write( "(A)9 (B) 11 (C) 13.5 (D) 15 (E) 18.5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #204446 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=204446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sharon runs a single lap on a track in 100 seconds. Jessica runs the same lap in 90 seconds. If both start at the same time from the same point on the track and each maintains a constant rate, the number of minutes before Jessica laps Sharon is:<BR>\n" );
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document.write( "On each lap Sharon gains 10 seconds on Jessi's time.<BR>\n" );
document.write( "In 9 laps Sharon will have gained a full lap on Jessi.<BR>\n" );
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document.write( "9 laps will take Sharon 900 seconds<BR>\n" );
document.write( "900 seconds = 900/60 = 15 minutes<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "(A)9 (B) 11 (C) 13.5 (D) 15 (E) 18.5<BR>\n" );
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