document.write( "Question 280586: The hypotenuse of a given right triangle is 6 cm longer than the
\n" ); document.write( "shorter leg. The length of the shorter leg is 2 cm less than that of the longer
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Algebra.Com's Answer #204441 by stanbon(75887)\"\" \"About 
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The hypotenuse of a given right triangle is 6 cm longer than the
\n" ); document.write( "shorter leg. The length of the shorter leg is 2 cm less than that of the longer
\n" ); document.write( "leg.
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\n" ); document.write( "Let shorter leg be \"x\".
\n" ); document.write( "Other leg is \"x+2\"
\n" ); document.write( "Hypotenuse = \"x+6\"
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\n" ); document.write( "Use Pythagoras to solve for \"x\" and the length of each side.
\n" ); document.write( "(x+6)^2 = x^2 + (x+2)^2
\n" ); document.write( "x^2 + 12x + 36 = 2x^2 + 4x+4
\n" ); document.write( "x^2 - 8x - 32 = 0
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\n" ); document.write( "Quadratic Formula:
\n" ); document.write( "x = [8 +- sqrt(64-4*-32)]/2
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\n" ); document.write( "x = [8 +- sqrt(192)]/2
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = (8 + sqrt(192))/2
\n" ); document.write( "x = 10.93 cm (shorter leg)
\n" ); document.write( "x+2 = 12.93 cm (other leg)
\n" ); document.write( "x+6 = 16.93 cm (hypotenuse)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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